(3x+4)(3x^2-20x+12)=0

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Solution for (3x+4)(3x^2-20x+12)=0 equation:


Simplifying
(3x + 4)(3x2 + -20x + 12) = 0

Reorder the terms:
(4 + 3x)(3x2 + -20x + 12) = 0

Reorder the terms:
(4 + 3x)(12 + -20x + 3x2) = 0

Multiply (4 + 3x) * (12 + -20x + 3x2)
(4(12 + -20x + 3x2) + 3x * (12 + -20x + 3x2)) = 0
((12 * 4 + -20x * 4 + 3x2 * 4) + 3x * (12 + -20x + 3x2)) = 0
((48 + -80x + 12x2) + 3x * (12 + -20x + 3x2)) = 0
(48 + -80x + 12x2 + (12 * 3x + -20x * 3x + 3x2 * 3x)) = 0
(48 + -80x + 12x2 + (36x + -60x2 + 9x3)) = 0

Reorder the terms:
(48 + -80x + 36x + 12x2 + -60x2 + 9x3) = 0

Combine like terms: -80x + 36x = -44x
(48 + -44x + 12x2 + -60x2 + 9x3) = 0

Combine like terms: 12x2 + -60x2 = -48x2
(48 + -44x + -48x2 + 9x3) = 0

Solving
48 + -44x + -48x2 + 9x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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